/*poj 3335 Rotating Scoreboard - 半平面交点是顺时针给出的*/#include 
    
     #include
     
      const double eps=1e-8;const int N=103;struct point{    double x,y;}dian[N];inline bool mo_ee(double x,double y){	double ret=x-y;	if(ret<0) ret=-ret;	if(ret
      
        y + eps;} // x > yinline bool mo_ll(double x,double y)  {   return x < y - eps;} // x < yinline bool mo_ge(double x,double y) {   return x > y - eps;} // x >= yinline bool mo_le(double x,double y) {   return x < y + eps;} 	// x <= yinline double mo_xmult(point p2,point p0,point p1)//p1在p2左返回负，在右边返回正{    return (p1.x-p0.x)*(p2.y-p0.y)-(p2.x-p0.x)*(p1.y-p0.y);}//求多边形面积double mo_area_polygon(point *dian,int n){	int i;	point yuan;	yuan.x=yuan.y=0;	double ret=0;	for(i=0;i